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Steelers Fall to Last in AFC North, Seventh in AFC Wild Card Picture

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The Cleveland Browns’ win over the Baltimore Ravens on Sunday moved the Pittsburgh Steelers into sole possession of last place in the AFC North, with the Browns moving out of a tie with Pittsburgh by a half-game.

It did move the Ravens back to the pack, though. First-place Baltimore is now 8-5, one game ahead of 7-6 Cleveland and the Cincinnati Bengals, who lost to the San Francisco 49ers in overtime. The Browns currently have the head-to-head tiebreaker over the Bengals, thanks to a 41-16 win in Cincinnati on Nov. 7.

The Steelers are a half-game behind those two teams at 6-6-1. The AFC North is the only of the NFL’s eight divisions where all four teams remain .500 or better.

In the NFC, the Steelers would be in playoff position at 6-6-1, behind only the 8-4 Los Angeles Rams and 7-6 49ers for Wild Card teams.

But the AFC is far more competitive. Pittsburgh is behind the 8-5 Los Angeles Chargers and five teams tied at 7-5 (Cincinnati, Cleveland, the Buffalo Bills, Indianapolis Colts and Denver Broncos).

AFC NORTH STANDINGS

Baltimore Ravens 8-5 (1-3)
Cleveland Browns 7-6 (2-2)*
Cincinnati Bengals 7-6 (3-1)
Pittsburgh Steelers 6-6-1 (2-2)

*Advanced due to head-to-head tiebreaker.

AFC WILD CARD STANDINGS

Los Angeles Chargers 8-5 (5-3)
Indianapolis Colts 7-6 (6-3)^
Buffalo Bills 7-6 (5-5)^
– – –
Cleveland Browns 7-6 (4-5)*^
Cincinnati Bengals 7-6 (5-3)^
Denver Broncos 7-6 (3-5)
Pittsburgh Steelers 6-6-1 (4-4)
Las Vegas Raiders 6-7 (4-4)*
Miami Dolphins 6-7 (4-5)

*Advanced due to head-to-head tiebreaker.
^Advanced due to conference record tiebreaker.