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Steelers Fall to Last in AFC North, Seventh in AFC Wild Card Picture



The Cleveland Browns’ win over the Baltimore Ravens on Sunday moved the Pittsburgh Steelers into sole possession of last place in the AFC North, with the Browns moving out of a tie with Pittsburgh by a half-game.

It did move the Ravens back to the pack, though. First-place Baltimore is now 8-5, one game ahead of 7-6 Cleveland and the Cincinnati Bengals, who lost to the San Francisco 49ers in overtime. The Browns currently have the head-to-head tiebreaker over the Bengals, thanks to a 41-16 win in Cincinnati on Nov. 7.

The Steelers are a half-game behind those two teams at 6-6-1. The AFC North is the only of the NFL’s eight divisions where all four teams remain .500 or better.

In the NFC, the Steelers would be in playoff position at 6-6-1, behind only the 8-4 Los Angeles Rams and 7-6 49ers for Wild Card teams.

But the AFC is far more competitive. Pittsburgh is behind the 8-5 Los Angeles Chargers and five teams tied at 7-5 (Cincinnati, Cleveland, the Buffalo Bills, Indianapolis Colts and Denver Broncos).


Baltimore Ravens 8-5 (1-3)
Cleveland Browns 7-6 (2-2)*
Cincinnati Bengals 7-6 (3-1)
Pittsburgh Steelers 6-6-1 (2-2)

*Advanced due to head-to-head tiebreaker.


Los Angeles Chargers 8-5 (5-3)
Indianapolis Colts 7-6 (6-3)^
Buffalo Bills 7-6 (5-5)^
– – –
Cleveland Browns 7-6 (4-5)*^
Cincinnati Bengals 7-6 (5-3)^
Denver Broncos 7-6 (3-5)
Pittsburgh Steelers 6-6-1 (4-4)
Las Vegas Raiders 6-7 (4-4)*
Miami Dolphins 6-7 (4-5)

*Advanced due to head-to-head tiebreaker.
^Advanced due to conference record tiebreaker.